Exercise 10.2: In a university with a total of 10,000 students, 20% of the students are business majors. A random sample of 100 students is selected, and their majors are recorded. Compute the standard error of the proportion. What is the probability that the sample of 100 students contains between 12 and 14 business majors?

Step-by-step explanation:

Compute the standard error of the proportion.

sqrt[pq/n] = sqrt[0.2*0.8/100]  = 0.04

p = 20%, q = 1- 20%

What is the probability that the sample contains between 12 and 14 business majors?

P(12≤X≤14) = P(X≤14) - P(X≤12)

= binomcdf(100,0.2,14)-binomcdf(100,0.2,11) = 0.0804 - 0.0126 = 0.0679

2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.