Consider the probability that no less than 99 out of 150 cell phone calls will not be disconnected. Assume the probability that a given cell phone call will not be disconnected is 63%. Approximate the probability using the normal distribution. Round your answer to four decimal places.

The probability that no less than 99 out of 150 cell phone calls will not be disconnected = P(x > 99) = 0.2240

Step-by-step explanation:

The mean = μ = np = 150 × 0.63 = 94.5

The standard deviation of the sample is given as √(np(1-p))

σ = √(150×0.63×0.37) = 5.91

For normal distribution, we will need to normalize the given variable whose probability we seek.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (99 - 94.5)/5.91 = 0.76

To determine the probability that no less than 99 out of 150 cell phone calls will not be disconnected = P(x > 99) = P(z > 0.76)

We'll use data from the normal probability table for these probabilities

P(x > 99) = P(z > 0.76) = 1 - P(z ≤ 0.76) = 1 - 0.776 = 0.2240

7,24

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.