A certain system can experience three different types of defects. Let Ai (i = 1,2,3) denote the event that the system has a defect of type i. Suppose that the following probabilities are true.

P(A1) = 0.12 P(A2) = 0.08 P(A3) = 0.05P(A1 U A2) = 0.14 P(A1 n A3) = 0.14P(A2 U A3) = 0.11 P(A1 n A2 n A3) = 0.01
(a) Given that the system has a type 1 defect, what is the probability that it has a type 2 defect? (Round your answer to four decimal places.)

Probability is 0.06

Step-by-step explanation:

From the question, we can see that it says the system already has a type 1 defect.

So for it to have a type 2 defect also, it means it will now have type 1 and 2 defect and thus; P(A1 ∩ A2)

And P(A1 ∩ A2) = P(A1) + P(A2) − P(A1 ∪ A2)

And from the question,

P(A1) = 0.12

P(A2) = 0.08

P(A1 ∪ A2) = 0.14

So, P(A1 ∩ A2) = 0.12 + 0.08 - 0.14 = 0.06

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.