In △ABC,∠B is a right angle. The coordinates for each point are A(10, 7), B(5, 9), and C(3, 4). Rounded to the nearest tenth, what is the area, in square units, of △ABC ? Enter the area in the box.

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

the formula to calculate the distance between two points is equal to

we have

A(10, 7), B(5, 9), and C(3, 4)

step 1

Find the distance AB

A(10, 7), B(5, 9)

substitute in the formula

step 2

Find the distance BC

B(5, 9),C(3, 4)

substitute in the formula

step 3

Find the area

substitute the values

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

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