Check the boxes which make the statement correct:
If the det()=0 then

A. given any there is one and only one which will satisfy the equation.
B. some values of (such as =0 ) will allow more than one to satisfy the equation.
C. given any there is one and only one which will satisfy the equation.
D. some values of will have no values of which will satisfy the equation.
E. there is no value of which satisfies the equation when =0.