For the functions f(x)=−x2+2x−1 and g(x)=x−1, find (fg)(x) and (fg)(0).

The answer to your question is  (fg)(x) = x² - 2; (fg)(0) = -2

Step-by-step explanation:

Data

f(x) = x² + 2x - 1

g(x) = x - 1

(fg)(x) = ?

(fg)(0) = ?

Process

1.- Evaluate f(x) in g(x)

f(g)(x) = (x -1)² + 2(x - 1) - 1

- Simplify

(fg)(x) = x² - 2x + 1 + 2x - 2 - 1

(fg)(x) = x² - 2

2.- Evaluate (fg)(x) when x = 0

(fg)(0) = (0)² - 2

- Simplify

(fg)(0) = 0 - 2

(fg)(0) = -2

d

step-by-step explanation:

4th option is correct xy=-10

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