RSM problem need help (picture included)
#2

O, A, T, R, I

Step-by-step explanation:

O, A, and T should work, because they are on Quadrant 2, where all x coordinates are negative and all y coordinates are positive.

O

- 5,  5

- 5 < 5

O works.

A

- 4, 1

- 4 < 1

A works.

T

- 7, 2

- 7 < 2

T works.

R

- 6, - 4

- 6 < - 4

R works.

I

3, 4

3 < 4

I works.

N

3, 3

3 = 3

N does not work.

P

- 4, - 4

- 4 = - 4

P does not work.

K

- 3, - 6

- 3 > - 6

K does not work.

B

7, 5

7 > 5

B does not work.

M

6, 0

6 > 0

M does not work.

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

i think the answer would be c