The sum of two numbers is 21.the second number is six times the first number. work out the two numbers

3 and

18

Step-by-step explanation:

Let the two numbers be A and B

Given the sum of the two numbers is 21.

That’s

A + B = 21

The second number is 6 times the first .

That’s

B = 6A

We now have two equations

Equation 1: A + B = 21

Equation 2: B = 6A

Now substitute 6A for B in equation 1

We have

A + 6A = 21

7A = 21

Divide both sides by 7

A = 21/7

A = 3

Substitute 3 for A in either of the equations to get B.

Using equation 2 , we have

B = 6A

B = 6 x 3

B = 18

The numbers are 3 and 18

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2