Solve for x and y:
12x = 4y - 4
y = 3x + 1

A) There are an infinite number of solutions.

B) The solution is (12, 12).

C) x = 0, y = 1

D) There is no solution.

A= I think because it is definite not c so there is a solution differently I know so that is my final answer.

Sorry if I am wrong.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

its an acute right triangle

step-by-step explanation: