* A turtle and a snail start moving towards each other when they are 200 feet apart. The turtle is running at a speed of T feet per minute, and the snail is moving at a speed of S feet per minute.
b
How soon will they meet?

time= 200 feet/ (T+S)

Step-by-step explanation:

In the beginning, the distance between the snail and the turtle is 200 feet. Then the turtle moving at T feet per minute so the distance will become 200-T feet after 1 minute. But the snail also moving at S feet per second, so the distance will be reduced into 200- (T+S) after 1 minute.  

The 200 feet distance will keep decreased slowly by both the turtle and the snail speed(T+S). They will meet when they both travel 200 feet The equation for distance is :

distance= speed * time

We are asked when they will meet(time). If you change the equation to solve for time, it will be:

200 feet = (T+S) * time

time= 200 feet/ (T+S)

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right