A set of different sized recatangles have the same area. one has a length of 4cm and width of 12cm . what is the lenght of a rectangle with width of 3cm.

The length of the 2nd rectangle is 16 cm.

Step-by-step explanation:

Given,

1st rectangle of having length (L) = 4 cm and width (B) = 12 cm

2nd rectangle of having width = 3 cm

They are of same are.

To find the length of the 2nd rectangle

Formula,

The area of rectangle = L×B sq cm

Area of 1st rectangle = 12 × 4 sq cm = 48 sq cm

According to the problem,

Length × 3 = 48

or, length = cm = 16 cm

The length of the 2nd rectangle is 16 cm.

L = 16cm

Step-by-step explanation:

Given the rectangles have the same area,

Area = length x width

Area of the one with length 4cm and width 12cm

= L x w

= 4 x 12

= 48 square centimeters

Now , length of rectangle with width 3cm ?

Recall that the rectangles have the same area.

So,

48 = L x 3

Divide both sides by 3

48/3 = L x 3/3

16 = L

L = 16cm

The Length of a rectangle with width of 3cm is 16cm

33/100 is what i got