A truck can be rented from Company A for $140 a day plus $0.40 per mile. Company B charges $60 a day plus $0.80 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Company A less than the rental cost of Company B?

the number of miles must be greater than 200.

Step-by-step explanation:

Let x represent the number of miles driven with trucks of either company A or company B.

Company A for $140 a day plus $0.40 per mile. This means that the total amount that Company A would charge for x miles in a day is

0.4x + 140

Company B charges $60 a day plus $0.80 per mile to rent the same truck. This means that the total amount that Company B would charge for x miles in a day is

0.8x + 60

For the rental cost for Company A to be less than the rental cost of Company B, the number of miles would be

0.4x + 140 < 0.8x + 60

0.4x - 0.8x < 60 - 140

- 0.4x < - 80

Dividing through by - 4, it becomes

x > - 80/ - 0.4

x > 200

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.