The length of a room is two times its breadth and breath is 2 times its height. if the volume of the room is 512 m*3.how much is the cost of plastering the wall at 5.50 per m*2?

It will cost 2,464 currency for plastering 448 of the wall.

Step-by-step explanation:

Step 1:

The volume of this room is determined by multiplying its length, breadth, and height.

From the question;

So

Step 2:

The volume of the room ,

Substituting the values of length and breadth in the above equation, we get

So

So l = 16 m, w = 8 m and h = 4 m.

Step 3:

If each of the wall costs 5.50, we need to calculate the surface area of the room.

There are six sides of the room (2 sets of 3 sides)

Area of the set =

Area of the set =

Area of the set =

The Surface area of these three sets = 128 + 64 + 32 = 224 .

Since there are two sets,

The total surface area = .

Step 4:

If each of the wall costs 5.50,

448 costs; currency.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2