A shopkeeper bought two watches at Rs 500.he sold one at loss of 12%and other at the profit of 8%.he neither gained nor loss at this transaction. Find the cost price

Step-by-step explanation:

Let CP of one watch = x

CP of second watch = 500 - x

SP of first watch = (100-12)% of x = 88% of x=0.88x

SP of second watch = (100+8)% of (500 - x) = 108% of (500 - x)

                                  = 1.08*(500 - x) = 1.08*500 - 1.08*x

                                   = 540 - 1.08x

Sp of two watches = 500

0.88x + 540 - 1.08x = 500

-0.20x + 540 = 500

-0.20x = 500 - 540

-0.20x = -40

x = -40/-0.20 = 40*100/20 = 2*100 = 200

CP of first watch = 200

CP of second watch = 500 - 200 = 300

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

where are the graphs?

step-by-step explanation: