Suppose that a fair, 6 sided die is rolled. Let X indicate the event that an even number is rolled (in other words, X = 1 if an even number is rolled and X = 0 otherwise). Let Y indicate the event that 2, 3, or 4 is rolled (in other words, Y = 1 if 2, 3, or 4 is rolled and Y = 0 otherwise). Find P (X = 0, Y = 1).

1/2, 1/2

Step-by-step explanation:

A die has 6 faces.

Total number of faces = 6

Possible outcomes are :1,2,3,4,5,6

Even numbers : 2, 4, and 6 = 3

Non even numbers: 1,3,and 5= 3

First statement:

P(Even number) = 3/ 6 = 1/2

P(X=1) = 1/2

P(odd number) = 3/6 = 1/2

P(X=0) = 1/2

Second statement:

P(2) = 1/6

P(3) = 1/6

P(4) = 1/6

P(2 or 3 or 4) = (1/6) + (1/6) + (1/6)

P(2 or 3 or 4) = (1+1+1)/6 = 3/6 =1/2

Thus,

P(Y=1) = 1/2

Therefore,

P(X =0,Y=1) = 1/2, 1/2

kk.bj.

step-by-step explanation:

.mnm.kn.kj

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6