A small mail order firm Seas Beginnings has one phone line. An average of 60 people per hour call in orders and it takes an average of 1 minute to handle a call. The time between calls and the time to handle calls are exponentially distributed. If the phone line is busy, Seas Beginnings can put up to c - 1 people on hold. If c - 1 people are on hold, a caller gets a busy signal and calls a competitor (Air End). Seas Beginnings wants only 1% of all callers to get a busy signal. How many people should the company be able to put on hold?

No. of Persons= 16

Step-by-step explanation:

There was a one phone line

Average no of people calling = 60 in one hour

% of all callers at most can get busy signal

Probability < 0.6

Probability for less than 1 person on hold = 0.2642

No of persons = 0.2642(60)

= 15.852 or 16

16 persons in hour the company is able to put on hold

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

answer: -0.5 would be the most likley outcome

step-by-step explanation: