The sum of three integers is 211. The sum of the first and second integer exceeds the third by 39. The third interference is 23 less than the first. Find the three integers.

A= 109 B= 16 C=86

Step-by-step explanation:

Write an equation for each statement:

:

"The sum of three integers is 211."

a + b + c = 211

:

"The sum of the first an second integers exceeds the third by 39."

a + b = c + 39

a + b - c = 39

:

"The third integer is 23 less than the first."

c = a - 23:

Subtract the 2nd equation from the 1st equation

a + b + c = 211

a + b - c = 39

subtraction eliminates a and b, find c

2c = 172

c = 86:

Find a using the 3rd equation

86 = a - 23

86 + 23 = a

a = 109

:

Find b using the 1st equation

109 + b +86 = 211

b = 211 - 195

b = 16

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: