A production manager at a wall clock company wants to test their new wall clocks. The designer claims they have a mean life of 17 years with a standard deviation of 4 years. If the claim is true, in a sample of 48 wall clocks, what is the probability that the mean clock life would be greater than 18 years

Probability that the mean clock life would be greater than 18 years is 0.04182 .

Step-by-step explanation:

We are given that the designer claims they have a mean life of 17 years with a standard deviation of 4 years.

Let X bar = mean clock life

The z score probability distribution is given by;

             Z = ~ N(0,1)

where,   = population mean life = 17 years

            = standard deviation = 4 years

            n = sample of wall clocks = 48

So, the probability that the mean clock life would be greater than 18 years is given by, P(X bar > 18 years);

   P(X bar > 18) = P( < ) = P(Z > 1.73) = 1 - P(Z <= 1.73)

                                                                              = 1 - 0.95818 = 0.04182

Therefore, the probability that the mean clock life would be greater than 18 years is 0.04182 .

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.