Solve the system by elimination

{

2x + 5y = −24

3x − 5y = 14

The answer to your question is x = -22; y = 4

Step-by-step explanation:

System of equations

                                  2x + 5y = -24         l

                                  3x - 5y = 14             ll

Process

1.- Multiply equation l equation l by 3 and equation ll by -2

                                  6x + 15y = -72

                                 -6x + 10y = -28    Add the equations

                                   0  + 25y = 100    

2.- Solve for y

                                             y = 100/25

                                             y = 4

3.- Substitute y in equation l to find x

                                     2x + 5(4) = -24

Solve for x

                                      2x + 20 = -24

                                      2x = -24 - 20

                                      2x = -44

                                        x = -44/2

                                        x = -22                                            

x = - 2, y = - 4

Step-by-step explanation:

The given system of equations is expressed as

2x + 5y = −24- - - - - - - - - - - - 1

3x − 5y = 14- - - - - - - - - - - - - - 2

We would eliminate x by multiplying equation 1 by 3 and equation 2 by 2. It becomes

6x + 15y = - 72

6x - 10y = 28

Subtracting, it becomes

15y - - 10y = - 72 - - 28

25y = - 100

Dividing the left hand side and the right hand side of the equation by 25, it becomes

25y/25 = - 100/25

y = - 4

Substituting y = - 4 into equation 1, it becomes

2x + 5 × - 4= −24

2x - 20 = 24

2x = - 24 + 20 = - 4

x = - 4/2 = - 2

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5

a is the correct