The Springfield Middle School sixth-grade teachers of history, science, and art are listed in the table.

Sixth Grade Teachers

History

Science

Art

Mr. Nelson

Ms. Porter

Mr. Rosenberger

Ms. Hogan

Mr. Grist

Ms. Patel

Ms. Miller

Ms. O’Reilly

Ms. George

Mr. Springer

Ms. Trufant

Ms. Callahan

Ms. Daniels

Mr. Pollard

Ms. Cartwright

Ms. Davis

Mr. Bergeron

Mr. Cooper

Mr. Chin

Mr. Dawson

Ms. Sarno

How many combinations of one history, one science teacher, and one art teacher include Mr. Bergeron?

13
36
252
288

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

da freeck kinda math is this just drop out

step-by-step explanation: