Suppose that pulse rates among healthy adults are normally distributed with a mean of 80 beats/second and a standard deviation of 8 beats/second. What proportion of healthy adults have pulse rates that are more than 83 beats/sec? Round your answer to at least four decimal places.

0.3520

Step-by-step explanation:

We have been given that the pulse rates among healthy adults are normally distributed with a mean of 80 beats/second and a standard deviation of 8 beats/second. We are asked to find the proportion of healthy adults have pulse rates that are more than 83 beats/sec.

First of all, we will find z-score corresponding to sample score of 83 as:

, where,

z = Z-score,

x = Sample score,

= Mean,

= Standard deviation.

Upon substituting our given values in z-score formula, we will get:

Now, we need to find the probability that a z-score is greater than 0.38.

Using formula , we will get:

Using normal distribution table, we will get:    

Therefore, 0.3520 of healthy adults have pulse rates that are more than 83 beats/sec.

r = 78539458390583095803458309458039485093485 or just 3

step-by-step explanation: