A car company developed a certain car model to appeal to young consumers. The car company claims the average age of drivers of this certain car model is26.00 years old. Suppose a random sample of 18 drivers was drawn, and the average age of the drivers was found to be 28.70 years. Assume the standard deviation for the age of the car drivers to be 2.3 years. Complete parts a through c below. a. Construct a 95% confidence interval to estimate the average age of the car driver. The 95% confidence interval for the average age of the car driver has a lower limit of years old and an upper limit of years old.

95% confidence interval for the average of the car driver has a lower limit of 27.56 years old and an upper limit of 29.84 years old.

Step-by-step explanation:

Confidence interval = mean + or - Error margin (E)

mean = 28.70 years

sd = 2.3 years

n = 18

degree of freedom = n - 1 = 18 - 1 = 17

confidence level = 95%

t-value corresponding to 17 degrees of freedom and 95% confidence level is 2.110

E = t × sd/√n = 2.110 × 2.3/√18 = 1.14 years

Lower limit = mean - E = 28.70 - 1.14 = 27.56 years

Upper limit = mean + E = 28.70 + 1.14 = 29.84 years

95% confidence interval is between 27.56 and 29.84 years.

what is the original number? you forgot to add it.

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.