Two submarines, one red and one blue, started rising toward the surface at the same time. they each rose at a constant speed. the red submarine started rising from an altitude of 80 meters below the surface. after 30 seconds it was 60 meters below the surface. The following equation gives the altitude (in meters relative to the surface) of the blue submarine as a function of time (in seconds) A=-90+0.6t

Step-by-step explanation:

Blue started at -90 meters at t=0. Red started at -80 meters, according to the problem statement. So Red started higher.

Red rose at 20 meters in 30 seconds, or 20/30 = 2/3 meters per second.

Blue's equation has a depth term of 0.6t that indicates it rises at 0.6 meters per second. We know that 2/3 ≈ 0.6667 > 0.6, so Red rises faster

so...

The graph of the red and blue depths shows red starts above blue and has a steeper rate of rise.

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

366

step-by-step explanation: