Howard will select two pieces of candy from a bowl with 5 chocolate candies, 4 gummy candies and 6 hard candies. What is Howard's probability of choosing a chocolate candy, eating it, then choosing a gummy candy?

9.5%.

Step-by-step explanation:

The probability in this case is calculated by publishing the probability of each event. That is, the first event of taking out one of chocolate and then taking out a gummy one where there is one less chocolate.

Therefore, in total they are 5 + 4 + 6 = 15 sweets.

Therefore the probability of getting one of chocolate is:

5/15 = 1/3

Now, in the second event there is one less sweet, that is, 14. Therefore the probability of taking out a gummy one is:

4/14 = 2/7

Then the final probability would be:

(1/3) * (2/7) = 0.095 = 9.5%

The probability of what the statement says is 9.5%.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day