Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile if she continued this pattern when was the first time she ran more that 1 mile explain

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form , where,

= nth term of sequence,

= 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.

We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

step-by-step explanation:

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step-by-step explanation: