A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. A random sample of 28 rounds of golf had a sample standard deviation of 3.5. Using α = 0.10, the conclusion for this hypothesis test would be that because the test statistic is . between the lower and upper critical values, we reject the null hypothesis and cannot conclude that the variance for this golfer's scores is not equal to 10.0 more than the upper critical value, we can reject the null hypothesis and conclude that the variance for this golfer's scores is not equal to 10.0 less than the lower critical value, we fail to reject the null hypothesis and conclude that the variance for this golfer's scores is not equal to 10.0 between the lower and upper critical values, we fail to reject the null hypothesis and cannot conclude that the variance for this golfer's scores is not equal to 10.0 Using α = 0.10, the lower critical value for this hypothesis test would be . 17.334 16.151 13.848 12.401 The test statistic for this hypothesis test would be . 33.08 40.75 12.57 46.23 The correct hypothesis statement would be . H0: σ2 = 10.0; H1: σ2 ≠ 10.0 H0: μ = 10.0; H1: μ ≠ 10.0 H0: σ = 10.0; H1: σ ≠ 10.0 H0: σ2 ≤ 10.0; H1: σ2 > 10.0

Step-by-step explanation:

Hello!

Interest hypothesizes is that the variance of the golfer's scores equals to δ²= 10.0.

A random sample of 28 rounds of golf had a sample standard deviation S= 3.5

The statistics hypotheses are:

H₀: δ²= 10.0

H₁: δ²≠ 10.0

α: 0.05

To conduct a hypothesis test for the population variance you have to work using the Chi-Square distribution, this test is two-tailed so you will have two critical values. Between these two values is defined as the "not rejection region" and below and above them lies the "rejection region"

Lower critical value:

Upper critical value:

If ≤ 16.928 or ≥ 40.113, the decision is to reject the null hypothesis.

If 16.928 < < 40.113, the decision is to not reject the null hypothesis.

The calculated is between the two critical values, so the decision is to not reject the null hypothesis. We can conclude that the population variance fro this golfers play score is 10.

I hope this helps!

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: