Can a pentagon have angles that measure 95°, 67°, 105°, 95°, and 177°?

No, it cannot have angles that measure 95°, 67°, 105°, 95°, and 177°.

Step-by-step explanation:

S = (n-2) * 180

A pentagon has 5 sides, so substitute n for sides (n = 5)

s = 5-2) * 180 = 540°

95° +  67° + 105° + 95° + 177° = 539°

Hope that Helps!

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

answer: idk

step-by-step explanation: