The probability that a randomly selected person has high blood pressure (the event H) is P(H) = 0.3 and the probability that a randomly selected person is a runner (the event R) is P(R) = 0.3. The probability that a randomly selected person has high blood pressure and is a runner is 0.1. Find the probability that a randomly selected person either has high blood pressure or is a runner or both.

0.5

Step-by-step explanation:

P(H) = 0.3

P(R) = 0.3

P(H⋂R) = 0.1 (probability that a randomly selected person has high blood pressure and is a runner)

Using the equation

P(H⋃R) = P(H) + P(R) - P(H⋂R)

This equation gives the probability of person either having high blood pressure or is a runner.

Substituting the values given:

P(H⋃R) = 0.3 + 0.3 - 0.1

P(H⋃R) = 0.5

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: