USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5P(x) 0.207 0.367 0.227 0.162 0.036 0.001(d) Compute μ, the expected number of repeat offenders out of five. (Round your answer to three decimal places.)μ =(e) Compute σ, the standard deviation of the number of repeat offenders out of five. (Round your answer to two decimal places.)σ = prisonersplease help

For the variance we need to calculate first the second moment given by:

And replacing we got:

And the variance is given by:

And the deviation is:

Step-by-step explanation:

For thi case we have the following distribution given:

X         0          1         2         3         4            5

P(X)  0.207  0.367 0.227  0.162  0.036    0.001

For this case the expected value is given by:

And replacing we got:

For the variance we need to calculate first the second moment given by:

And replacing we got:

And the variance is given by:

And the deviation is:

c

step-by-step explanation:

i think because what else can be a sample of every member

step-by-step explanation: