A triangle with vertices labeled as X, Y, and Z. Side X Z is base. Side Y X contains a midpoint M. A line segment drawn from Z to M bisects angle Y Z X into two parts labeled as Y Z M and X Z M. Angles Y Z M and X Z M are marked with single arc. Side Y Z is labeled 7. Base X Z is labeled 11. Side Y M is labeled 3.5.

The value of MX is 5.5 units.

Step-by-step explanation:

As the complete question is not given, the complete question is found online and is attached herewith

The diagram is attached with the solution.

As the line ZM is dividing the angle in two parts thus as the two angles are equal thus

The sides are given as

XZ=11

YM=3.5

YZ=7

Now by the theorem of the angles, the bisected angles are such that sin(<YZM)=sin(<XZM)

so

So the value of MX is 5.5 units.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!