Given the equation square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution. ^ i really don't understand this topic, whatsoever. could someone ?

Step-by-step explanation:

We have been given a square root equation . We are asked to solve for x.  

To solve our given equation, we will square both sides of our given equation as:

Using radical rule , we will get:

Upon subtracting 1 from both sides, we will get:

Now, we will divide both sides of our equation by 2.

We know that to find an extraneous solution, we need to substitute back the solution in original equation to check that if it satisfies original equation or not. If the solution does not satisfy original equation, then it is an extraneous solution.

Since both sides of our given equation are equal, therefore, is not an extraneous solution.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.