The length of a rectangle is 12 cm more than its width. Find the
area of the rectangle if its perimeter is 100 cm.

Dimensions of the rectangle (width and length) are 19 cm and 31 cm respectively.

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

100 = 2(x + 12 + x)

100 = 4x + 24

4x = 100 - 24 = 76

∴ x = 76/4 = 19 cm

∴ Length = 19 + 12 = 31 cm

it would be:

c.parallelogram.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet