In a quadrilateral ABCD, AB ∥ DC and AD ∥ BC . Find the perimeter of ΔCOD if point O is the intersection of the diagonals and AC = 20 in, BD = 20 in, AB = 13 in

33 inches

Step-by-step explanation:

In a quadrilateral ABCD, AB ∥ DC and AD ∥ BC.

AC = 20 in, BD = 20 in, AB = 13 in.

We want to find the perimeter of ΔCOD if point O is the intersection of the diagonals.

Since AB ∥ DC and AD ∥ BC, the point O divides the diagonals into two equal parts.

|OD|=|BD|/2 = 20/2 =10inch

Similarly,

|OC|=|AC|/2 = 20/2 =10inch

Also,

AB=CD=13 inch

Therefore,

Perimeter of ΔCOD= |OD|+|OC|+|CD|

=10+10+13

=33 inches

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°