![\left[\begin{array}{ccc}Time (s)&Height (ft)&Rate\ of\ change(ft/s)\\0.00&96.44\\&&\frac{97.60-96.44}{0.10-0.00}=11.6 \\0.10&97.60\\&&\frac{98.57-97.60}{0.30-0.10}=4.85\\0.30&98.57\\&&\frac{98.30-98.57}{0.60-0.30}=-0.90\\0.60&98.30\end{array}\right]](/tpl/images/0535/6852/582ad.png)
*SOMEONE WHO CAN SIMPLY ORDER INTERVALS!*
The table represents the height of a rock thro...
Mathematics, 06.03.2020 18:50 KaiKai11
*SOMEONE WHO CAN SIMPLY ORDER INTERVALS!*
The table represents the height of a rock thrown off the side of a bridge that is 96.44 feet above ground level for the first 0.60 seconds. Find the average rate of change for each interval and order the intervals from least to greatest rate of change.
Time (seconds) (left) / Height (feet)(right)
0.00 / 96.44
0.10 / 97.60
0.30 / 98.57
0.60 / 98.30
Answers: 1
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