The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 371 Ω, I = 0.09 A, dV/dt = −0.04 V/s, and dR/dt = 0.07 Ω/s. (Round your answer to six decimal places.)