Aset of data has a normal distribution with a mean of 5.1 and standard deviation of 0.9. find the percent of data between 6.0 and 6.9

The percent data between 6.0 and 6.9 would be 13.59%. Here’s the complete solution for this specific problem.

z = (X - Mean)/SD 
z1 = (6 - 5.1)/09 = + 1 
z2 = (6.9 - 5.1)/09 = + 2 
Required Percent = P(6 < X < 6.9)*100 
= P(1 < z < 2)*100 
= [P(z < 2) - P(z < 1)]*100 
= [0.9772 - 0.8413]*100 
= 0.1359*100 
= 13.59%

I am hoping that this has answered your query.

answer: for each 3 girls there is 2 boys . 3: 2

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5/20 so 25%

step-by-step explanation: