On a coordinate plane, a piecewise function has 2 lines. The first line has a closed circle at (negative 2, negative 2) and then goes up through (negative 4, 2) with an arrow instead of an endpoint. The second line has an open circle at (2, 1) and then goes up through (5, 4) with an arrow instead of an endpoint.

Which values are within the domain of the function? Check all that apply.

x = –6

x = –4

x = –2

x = 0

x = 2

x = 4

its A B C F

-4, -2 and 4

Step-by-step explanation:

Consider x represents the input value,

Given,

In the piece-wise function,

The first line has a closed circle at (-2, negative 2) and then goes up through (-4, 2) with an arrow instead of an endpoint.

Thus, -4 ≤ x ≤ -2.

The second line has an open circle at (2, 1) and then goes up through (5, 4) with an arrow instead of an endpoint.

Thus, 2 < x ≤ 5.

Since domain of a function is all possible input values,

Therefore, domain = [-4,-2]∪(2,5]

-6 ∉ [-4,-2]∪(2,5]

-4 ∈ [-4,-2]∪(2,5]

-2 ∈ [-4,-2]∪(2,5]

0 ∉ [-4,-2]∪(2,5]

2 ∉ [-4,-2]∪(2,5]

4 ∈ [-4,-2]∪(2,5]

Hence, -4, -2 and 4 are within the domain of the function.

55? i think maybe

step-by-step explanation:

translate k to n and reflect across the line containing jk.