A baseball team has 4 pitchers, who only pitch, and 16 other players, all of whom can play any position other than pitcher. For Saturday's game, the coach has not yet determined which 9 players to use nor what the batting order will be, except that the pitcher will bat last. How many different batting orders may occur?

2,075,673,600 batting orders may occur.

Step-by-step explanation:

The order of the first eight batters in the batting order is important. For example, if we exchange Jonathan Schoop with Adam Jones in the lineup, that is a different lineup. So we use the permutations formula to solve this problem.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

First 8 batters

8 players from a set of 16. So

Last batter:

Any of the four pitchers.

How many different batting orders may occur?

4*518918400 = 2,075,673,600

2,075,673,600 batting orders may occur.

step-by-step explanation:

y=x+9

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step-by-step explanation: