Has slope 3 and passes through (2, 2)

y=3x-4

Step-by-step explanation:

Lets make this into y=mx+b form

m(slope)

b(y intercept)

y=3x+b

Now plug in 2 for y and 2 for x (since the coordinantes are 2,2)

2=3(2)+b

Simplify like terms

2=6+b

-4=b

So b=-4 and m=3.

You got your equation, y=3x-4

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this