A horse race has 13 entries and one person owns 3 of those horses. Assuming that there are no ties, what is the probability that those three horses finish first comma second and third (regardless of order)?

answer:

c(11,4) = 11! / (4! * 7!) = (11 * 10 * 9 * 8 * 7!) / (4! * 7!) = (11 * 10 * 9 * 8) / (4 * 3 * 2 * 1) = 330.

Step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

need more info

step-by-step explanation: