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Mathematics, 05.03.2020 00:06 ajayrose

Check that the point (1,βˆ’1,3) lies on the given surface. Then, viewing the surface as a level surface for a function f(x, y,z), find a vector normal to the surface and an equation for the tangent plane to the surface at (1,βˆ’1,3). 2x2βˆ’3y2+2z2=17

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Check that the point (1,βˆ’1,3) lies on the given surface. Then, viewing the surface as a level surfac...
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