Which point is on the circle centered at the origin with a radius of 5 units?
Distance formula: (x2 – x2)2 + (v2 - Yo)?
(2, 721)
(2, V23)
(2, 1)
(2,3)

(2,√21)

Step-by-step explanation:

The circle centered at the origin has equation:

Any point that satisfies this equation lie on this circle.

When x=2, we substitute and solve for y.

Take square root to get:

Therefore (2,-√21) and (2,√21) are on this circle.

From the options, (2,√21) is the correct answer

3rd box is the answer

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.