Why does (x-2)^2+9=0 have no real solutions?

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ±

yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to are said to be imaginary, that is ± 3i

where i =

If interested investigate further.

if you was gonna solve for a, a is a   < -12

the answer is: -22 also a

hope i

-lavira: )