A type of bacteria has a very high exponential growth rate of 80% every hour. If there are 10 bacteria, determine how many will be in 5 hours,1 day, and 1 week

Solution:

Given that,

A type of bacteria has a very high exponential growth rate of 80% every hour

There are 10 bacteria

The increasing function is given as:

Where,

y is future value

a is initial value

r is growth rate

t is time period

From given,

a = 10

Determine how many will be in 5 hours

Substitute t = 5

y = 189

Thus, there are 189 bacteria in 5 hours

Determine how many will be in 1 day ?

1 day = 24 hours

Substitute t = 24

Thus, there are 13382588 bacteria in 1 day

Determine how many will be in 1 week

1 week = 168

Substitute t = 168

Thus there are bacteria in 1 week

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)