A fish jumps out of the water at a speed of 12 feet per second. the height y (in feet) of the fish above the surface of the water is represented by the equation y=-16x²+12x, where x is the time (in seconds) since the jump began. the fish reaches its highest point above the surface of the water after 0.357 second. How far above the surface is the fish at this time?
(Someone PLEASE HELP)

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)