Cole has 4 regular dice and 1 unique dice that has the value 1 on each of the 6 faces. He picks one at random and rolls 3 ones in a row. What is the probability he picked the unique dice

0.008

Step-by-step explanation:

The probability of having chosen the unique dice three times in a row would be the multiplication of the probability of each event.

The event is always repeated. Take the single dice of 5 dice in total. Therefore the probability is 1/5.

Then the final probability would be:

(1/5) * (1/5) * (1/5), and that is equal to 0.008.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube