Solve this system of linear equations: 4x-2y=8 Y=3/2x-2

x = 4 , y = 4

Step-by-step explanation:

Solve the following system:

{4 x - 2 y = 8 | (equation 1)

y = (3 x)/2 - 2 | (equation 2)

Express the system in standard form:

{4 x - 2 y = 8 | (equation 1)

-(3 x)/2 + y = -2 | (equation 2)

Add 3/8 × (equation 1) to equation 2:

{4 x - 2 y = 8 | (equation 1)

0 x+y/4 = 1 | (equation 2)

Divide equation 1 by 2:

{2 x - y = 4 | (equation 1)

0 x+y/4 = 1 | (equation 2)

Multiply equation 2 by 4:

{2 x - y = 4 | (equation 1)

0 x+y = 4 | (equation 2)

Add equation 2 to equation 1:

{2 x+0 y = 8 | (equation 1)

0 x+y = 4 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 4 | (equation 1)

0 x+y = 4 | (equation 2)

Collect results:

{x = 4 , y = 4

depends on how many days you are talking about

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.