Calculate the distance between (4,6) and (5,0)

Th distance would be about 6.08 units

We can set this up using Pythagorean’s Theorem with the total distance between your two points as your hypotenuse.
First you want to find your legs (count up or down and go left or right however many times). First we need to find the distance from 4 to 5 (our x-values) so 5-4=1. There is a distance of 1 units. Next we need to find the distance from 6 to 0 (our y-values) 6-0=6. These will be our leg lengths.
Next use Pythagorean’s theorem and so 6^2+1^2=c^2. Now simplify and add and you’ll get 37=c^2. Next find the square root of both sides and you’ll get c≈6.08

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