Suppose that h(0) = 0, h(1) = 1 and for n ≥ 2, h(n) = 5h(n − 1) − 6h(n − 2) + 4 × 3 n. Use strong induction to show that h(n) = 35 × 2 n − 35 × 3 n + 12n3 n.

Given: △abc, ab=15, bd=9 ad ⊥ bc , m∠c=30°. find: the perimeter of the triangle.

Offering 30 if a plus b plus c equals 68 and ab plus bc plus ca equals 1121, where a, b, and c are all prime numbers, find the value of abc. the answer is 1978 but i need an explanation on how to get that.

Can someone show me step by step how to do this?