Sandra wants to rent a car to take a trip and has a budget of $90. There is a fixed rental fee of $30 and a daily fee of $10. Write an inequality that would be used to solve for the maximum number of days for which Sandra can rent the car on her budget. 30x + 10 ≤ 90 30 + 10x ≤ 90 30x + 10 ≥ 90 30 + 10x ≥ 90

Option B is the correct answer

Step-by-step explanation:

Step 1 :

Given,

Maximum budget Sandra has for the trip is $90

Fixed rental fee = $30

Daily fee = $10

Step 2 :

Let x be the number of the days for which Sandra can go for the trip

If the daily fee is $10, the cost for x number of days would be 10*x

the fixed fee is $30

So the equation is represent the cost of the trip is 30 + 10 x

given that the maximum budget is $90, the above cost should always be less $90

So the required inequality is 30 + 10x ≤ 90

Option B is the correct answer

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2